√70以上 1x+1+2x+25x+4

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1x+1+2x+25x+4. Edwin drew a scale drawing of a community college. Solve for x:1/x+1 +2/x+2 =5/x+4 - gvikasyadav509 is waiting for your help. Related Answers Basic Algebra Question For real numbers,a,b, and,c determine whether each statement is TRUE or FALSE (circle).

If FALSE, justify with an explanation. Share 11 1 x + 1 +. Add your answer and earn points.

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$\\Solution:\\ Given:\\\\ 4^x-4^{x-1}=24\\\\ \Rightarrow 4^x-\frac{4^x}{4}=24\ \ \ \ [\because a^{m-n}=\frac{a^m}{a^n}]\\\\\\ \Rightarrow 4^x(1-\frac{1}4)=24\\\\\ \Rightarrow 4^x\times\frac34=24\\\\\\ \Rightarrow 4^x=24\times\frac43\\\\\\\ \Rightarrow 4^x=32\\\\\\ \Rightarrow {(2^2)}^x=2^5\\\\ Bases\ are\ equal\ then\ the\ exponents\ are\ also\ equal\\\\ \Rightarrow 2x=5\\\\ \therefore x=\frac52\\\\ Now, \\ (2x)^x={(2\times\frac52)}^\frac52 =5^\frac52=\sqrt{5^5}=\sqrt{5^4\times5}=5^2\sqrt5=25\sqrt5$

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$\\Solution:\\\\ Given: x+\frac1x=5\\\\ \text{Squaring on both sides}\\\\ \Rightarrow (x+\frac1x)^2=5^2\\\\ \Rightarrow x^2+2\times x\times\frac1x+\left (\frac{1}{x} \right )^2=25\ \ \ \ \ \ \ \ [\because (a+b)^2=a^2+b^2+2ab]\\\\ \Rightarrow x^2+2+\frac{1}{x^2}=25\\\\ \Rightarrow x^2+\frac{1}{x^2}=25-2\\\\ \therefore \left (x^2+\frac{1}{x^2} \right )=23\\\\ \text{Squaring on both sides}\\\\ \Rightarrow \left (x^2+\frac{1}{x^2} \right )^2=23^2\\ \Rightarrow x^4+2\times x^2\times\frac1{x^2}+\left (\frac{1}{x^2} \right )^2=529\ \ \ \ \ \ \ \ [\because (a+b)^2=a^2+b^2+2ab]\\\\ \Rightarrow x^4+2+\frac{1}{x^4}=529\\\\ \Rightarrow x^4+\frac{1}{x^4}=529-2\\\\ \therefore \left (x^4+\frac{1}{x^4} \right )=527$

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